mfd: 88pm860x: Avoid to check resource for preg regulator

Since PREG regulator is the only one regulator in 88PM8606, and other
regulators are in 88PM8607. Checking resource as identifying regulator
is not a good way. We can use NULL resource to indentify PREG regulator.

Signed-off-by: Haojian Zhuang <haojian.zhuang@marvell.com>
Signed-off-by: Samuel Ortiz <sameo@linux.intel.com>
This commit is contained in:
Haojian Zhuang
2012-09-17 12:19:07 +08:00
committed by Samuel Ortiz
parent e7a7810ae0
commit ff13e9e256
2 changed files with 20 additions and 20 deletions

View File

@@ -150,10 +150,6 @@ static struct resource charger_resources[] __devinitdata = {
{PM8607_IRQ_VCHG, PM8607_IRQ_VCHG, "vchg voltage", IORESOURCE_IRQ,},
};
static struct resource preg_resources[] __devinitdata = {
{PM8606_ID_PREG, PM8606_ID_PREG, "preg", IORESOURCE_REG,},
};
static struct resource rtc_resources[] __devinitdata = {
{PM8607_IRQ_RTC, PM8607_IRQ_RTC, "rtc", IORESOURCE_IRQ,},
};
@@ -960,10 +956,8 @@ static void __devinit device_power_init(struct pm860x_chip *chip,
power_devs[2].platform_data = &preg_init_data;
power_devs[2].pdata_size = sizeof(struct regulator_init_data);
power_devs[2].num_resources = ARRAY_SIZE(preg_resources);
power_devs[2].resources = &preg_resources[0],
ret = mfd_add_devices(chip->dev, 0, &power_devs[2], 1,
&preg_resources[0], chip->irq_base, NULL);
NULL, chip->irq_base, NULL);
if (ret < 0)
dev_err(chip->dev, "Failed to add preg subdev\n");
}