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regulatory: remove handling of channel bandwidth

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The channel bandwidth handling isn't really quite right,
it assumes that a 40 MHz channel is really two 20 MHz
channels, which isn't strictly true. This is the way the
regulatory database handling is defined right now though
so remove the logic to handle other channel widths.

Signed-off-by: Johannes Berg <johannes.berg@intel.com>
This commit is contained in:
Johannes Berg
2012-12-04 15:07:34 +01:00
父節點 6913b49a50
當前提交 fe7ef5e9ba
共有 5 個文件被更改，包括 21 次插入 和 49 次删除
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7
drivers/net/wireless/ath/regd.c
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@@ -195,7 +195,6 @@ ath_reg_apply_beaconing_flags(struct wiphy *wiphy,
const struct ieee80211_reg_rule *reg_rule;
struct ieee80211_channel *ch;
unsigned int i;
u32 bandwidth = 0;
int r;
for (band = 0; band < IEEE80211_NUM_BANDS; band++) {
@@ -216,7 +215,6 @@ ath_reg_apply_beaconing_flags(struct wiphy *wiphy,
if (initiator == NL80211_REGDOM_SET_BY_COUNTRY_IE) {
r = freq_reg_info(wiphy,
ch->center_freq,
bandwidth,
&reg_rule);
if (r)
continue;
@@ -254,7 +252,6 @@ ath_reg_apply_active_scan_flags(struct wiphy *wiphy,
struct ieee80211_supported_band *sband;
struct ieee80211_channel *ch;
const struct ieee80211_reg_rule *reg_rule;
u32 bandwidth = 0;
int r;
sband = wiphy->bands[IEEE80211_BAND_2GHZ];
@@ -283,7 +280,7 @@ ath_reg_apply_active_scan_flags(struct wiphy *wiphy,
*/
ch = &sband->channels[11]; /* CH 12 */
r = freq_reg_info(wiphy, ch->center_freq, bandwidth, &reg_rule);
r = freq_reg_info(wiphy, ch->center_freq, &reg_rule);
if (!r) {
if (!(reg_rule->flags & NL80211_RRF_PASSIVE_SCAN))
if (ch->flags & IEEE80211_CHAN_PASSIVE_SCAN)
@@ -291,7 +288,7 @@ ath_reg_apply_active_scan_flags(struct wiphy *wiphy,
}
ch = &sband->channels[12]; /* CH 13 */
r = freq_reg_info(wiphy, ch->center_freq, bandwidth, &reg_rule);
r = freq_reg_info(wiphy, ch->center_freq, &reg_rule);
if (!r) {
if (!(reg_rule->flags & NL80211_RRF_PASSIVE_SCAN))
if (ch->flags & IEEE80211_CHAN_PASSIVE_SCAN)