sched: Fix signedness bug in yield_to()
yield_to() is supposed to return -ESRCH if there is no task to yield to, but because the type is bool that is the same as returning true. The only place I see which cares is kvm_vcpu_on_spin(). Signed-off-by: Dan Carpenter <dan.carpenter@oracle.com> Reviewed-by: Raghavendra <raghavendra.kt@linux.vnet.ibm.com> Signed-off-by: Peter Zijlstra <peterz@infradead.org> Cc: Gleb Natapov <gleb@kernel.org> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Paolo Bonzini <pbonzini@redhat.com> Cc: kvm@vger.kernel.org Link: http://lkml.kernel.org/r/20140523102042.GA7267@mwanda Signed-off-by: Ingo Molnar <mingo@kernel.org>
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Ingo Molnar

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@@ -2180,7 +2180,7 @@ static inline void sched_autogroup_fork(struct signal_struct *sig) { }
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static inline void sched_autogroup_exit(struct signal_struct *sig) { }
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#endif
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extern bool yield_to(struct task_struct *p, bool preempt);
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extern int yield_to(struct task_struct *p, bool preempt);
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extern void set_user_nice(struct task_struct *p, long nice);
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extern int task_prio(const struct task_struct *p);
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/**
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