ip6_tunnel: remove magic mtu value 0xFFF8

I don't know where this value comes from (probably a copy and paste and
paste and paste ...).
Let's use standard values which are a bit greater.

Link: https://git.kernel.org/pub/scm/linux/kernel/git/davem/netdev-vger-cvs.git/commit/?id=e5afd356a411a
Signed-off-by: Nicolas Dichtel <nicolas.dichtel@6wind.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
This commit is contained in:
Nicolas Dichtel
2018-05-31 10:59:33 +02:00
committed by David S. Miller
parent 82612de1c9
commit f7ff1fde94
2 changed files with 11 additions and 5 deletions

View File

@@ -1692,8 +1692,13 @@ int ip6_tnl_change_mtu(struct net_device *dev, int new_mtu)
if (new_mtu < ETH_MIN_MTU)
return -EINVAL;
}
if (new_mtu > 0xFFF8 - dev->hard_header_len)
return -EINVAL;
if (tnl->parms.proto == IPPROTO_IPV6 || tnl->parms.proto == 0) {
if (new_mtu > IP6_MAX_MTU - dev->hard_header_len)
return -EINVAL;
} else {
if (new_mtu > IP_MAX_MTU - dev->hard_header_len)
return -EINVAL;
}
dev->mtu = new_mtu;
return 0;
}
@@ -1841,7 +1846,7 @@ ip6_tnl_dev_init_gen(struct net_device *dev)
if (!(t->parms.flags & IP6_TNL_F_IGN_ENCAP_LIMIT))
dev->mtu -= 8;
dev->min_mtu = ETH_MIN_MTU;
dev->max_mtu = 0xFFF8 - dev->hard_header_len;
dev->max_mtu = IP6_MAX_MTU - dev->hard_header_len;
return 0;