block: Do away with the notion of hardsect_size

Until now we have had a 1:1 mapping between storage device physical
block size and the logical block sized used when addressing the device.
With SATA 4KB drives coming out that will no longer be the case.  The
sector size will be 4KB but the logical block size will remain
512-bytes.  Hence we need to distinguish between the physical block size
and the logical ditto.

This patch renames hardsect_size to logical_block_size.

Signed-off-by: Martin K. Petersen <martin.petersen@oracle.com>
Signed-off-by: Jens Axboe <jens.axboe@oracle.com>
This commit is contained in:
Martin K. Petersen
2009-05-22 17:17:49 -04:00
committed by Jens Axboe
szülő 9bd7de51ee
commit e1defc4ff0
54 fájl változott, egészen pontosan 108 új sor hozzáadva és 98 régi sor törölve

Fájl megtekintése

@@ -76,7 +76,7 @@ ibm_partition(struct parsed_partitions *state, struct block_device *bdev)
Sector sect;
res = 0;
blocksize = bdev_hardsect_size(bdev);
blocksize = bdev_logical_block_size(bdev);
if (blocksize <= 0)
goto out_exit;
i_size = i_size_read(bdev->bd_inode);

Fájl megtekintése

@@ -110,7 +110,7 @@ parse_extended(struct parsed_partitions *state, struct block_device *bdev,
Sector sect;
unsigned char *data;
u32 this_sector, this_size;
int sector_size = bdev_hardsect_size(bdev) / 512;
int sector_size = bdev_logical_block_size(bdev) / 512;
int loopct = 0; /* number of links followed
without finding a data partition */
int i;
@@ -415,7 +415,7 @@ static struct {
int msdos_partition(struct parsed_partitions *state, struct block_device *bdev)
{
int sector_size = bdev_hardsect_size(bdev) / 512;
int sector_size = bdev_logical_block_size(bdev) / 512;
Sector sect;
unsigned char *data;
struct partition *p;