debugfs: make debugfs_create_u32_array() return void

The single user of debugfs_create_u32_array() does not care about the
return value of it, so make it return void as there is no need to do
anything with the return value.

Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
This commit is contained in:
Greg Kroah-Hartman
2019-04-16 15:46:55 +02:00
parent 36b7ee4dce
commit c9c2c27d7c
3 changed files with 10 additions and 18 deletions

View File

@@ -133,9 +133,8 @@ struct dentry *debugfs_create_regset32(const char *name, umode_t mode,
void debugfs_print_regs32(struct seq_file *s, const struct debugfs_reg32 *regs,
int nregs, void __iomem *base, char *prefix);
struct dentry *debugfs_create_u32_array(const char *name, umode_t mode,
struct dentry *parent,
u32 *array, u32 elements);
void debugfs_create_u32_array(const char *name, umode_t mode,
struct dentry *parent, u32 *array, u32 elements);
struct dentry *debugfs_create_devm_seqfile(struct device *dev, const char *name,
struct dentry *parent,
@@ -353,11 +352,10 @@ static inline bool debugfs_initialized(void)
return false;
}
static inline struct dentry *debugfs_create_u32_array(const char *name, umode_t mode,
struct dentry *parent,
u32 *array, u32 elements)
static inline void debugfs_create_u32_array(const char *name, umode_t mode,
struct dentry *parent, u32 *array,
u32 elements)
{
return ERR_PTR(-ENODEV);
}
static inline struct dentry *debugfs_create_devm_seqfile(struct device *dev,