debugfs: make debugfs_create_u32_array() return void
The single user of debugfs_create_u32_array() does not care about the return value of it, so make it return void as there is no need to do anything with the return value. Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
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@@ -997,25 +997,19 @@ static const struct file_operations u32_array_fops = {
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* @array as data. If the @mode variable is so set it can be read from.
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* Writing is not supported. Seek within the file is also not supported.
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* Once array is created its size can not be changed.
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*
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* The function returns a pointer to dentry on success. If an error occurs,
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* %ERR_PTR(-ERROR) or NULL will be returned. If debugfs is not enabled in
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* the kernel, the value %ERR_PTR(-ENODEV) will be returned.
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*/
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struct dentry *debugfs_create_u32_array(const char *name, umode_t mode,
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struct dentry *parent,
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u32 *array, u32 elements)
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void debugfs_create_u32_array(const char *name, umode_t mode,
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struct dentry *parent, u32 *array, u32 elements)
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{
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struct array_data *data = kmalloc(sizeof(*data), GFP_KERNEL);
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if (data == NULL)
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return NULL;
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return;
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data->array = array;
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data->elements = elements;
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return debugfs_create_file_unsafe(name, mode, parent, data,
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&u32_array_fops);
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debugfs_create_file_unsafe(name, mode, parent, data, &u32_array_fops);
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}
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EXPORT_SYMBOL_GPL(debugfs_create_u32_array);
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