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x86/fpu: Simplify fpu->fpregs_active use

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The fpregs_active() inline function is pretty pointless - in almost
all the callsites it can be replaced with a direct fpu->fpregs_active
access.

Do so and eliminate the extra layer of obfuscation.

Cc: Andrew Morton <akpm@linux-foundation.org>
Cc: Andy Lutomirski <luto@amacapital.net>
Cc: Andy Lutomirski <luto@kernel.org>
Cc: Borislav Petkov <bp@alien8.de>
Cc: Dave Hansen <dave.hansen@linux.intel.com>
Cc: Eric Biggers <ebiggers3@gmail.com>
Cc: Fenghua Yu <fenghua.yu@intel.com>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Oleg Nesterov <oleg@redhat.com>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Rik van Riel <riel@redhat.com>
Cc: Thomas Gleixner <tglx@linutronix.de>
Cc: Yu-cheng Yu <yu-cheng.yu@intel.com>
Link: http://lkml.kernel.org/r/20170923130016.21448-16-mingo@kernel.org
Signed-off-by: Ingo Molnar <mingo@kernel.org>
This commit is contained in:
Ingo Molnar
2017-09-23 14:59:58 +02:00
parent 6d7f7da553
commit b3a163081c
4 changed files with 8 additions and 22 deletions
Download Patch File Download Diff File Expand all files Collapse all files

17
arch/x86/include/asm/fpu/internal.h
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@@ -542,21 +542,6 @@ static inline void fpregs_activate(struct fpu *fpu)
trace_x86_fpu_regs_activated(fpu);
}
/*
* The question "does this thread have fpu access?"
* is slightly racy, since preemption could come in
* and revoke it immediately after the test.
*
* However, even in that very unlikely scenario,
* we can just assume we have FPU access - typically
* to save the FP state - we'll just take a #NM
* fault and get the FPU access back.
*/
static inline int fpregs_active(void)
{
return current->thread.fpu.fpregs_active;
}
/*
* FPU state switching for scheduling.
*
@@ -617,7 +602,7 @@ static inline void user_fpu_begin(void)
struct fpu *fpu = &current->thread.fpu;
preempt_disable();
if (!fpregs_active())
if (!fpu->fpregs_active)
fpregs_activate(fpu);
preempt_enable();
}