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x86: Simplify __HAVE_ARCH_CMPXCHG tests

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Both the 32-bit and 64-bit cmpxchg.h header define __HAVE_ARCH_CMPXCHG
and there's ifdeffery which checks it. But since both bitness define it,
we can just as well move it up to the main cmpxchg header and simpify a
bit of code in doing that.

Signed-off-by: Borislav Petkov <bp@suse.de>
Link: http://lkml.kernel.org/r/20140711104338.GB17083@pd.tnic
Signed-off-by: H. Peter Anvin <hpa@linux.intel.com>
This commit is contained in:
Borislav Petkov
2014-07-11 12:43:38 +02:00
committed by H. Peter Anvin
parent 891715793f
commit b08ee5f7e4
6 changed files with 5 additions and 25 deletions
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2
arch/x86/include/asm/cmpxchg_64.h
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@@ -6,8 +6,6 @@ static inline void set_64bit(volatile u64 *ptr, u64 val)
*ptr = val;
}
#define __HAVE_ARCH_CMPXCHG 1
#define cmpxchg64(ptr, o, n) \
({ \
BUILD_BUG_ON(sizeof(*(ptr)) != 8); \