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debugfs: remove return value of debugfs_create_u64()

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No one checks the return value of debugfs_create_u64(), as it's not
needed, so make the return value void, so that no one tries to do so in
the future.

Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
Link: https://lore.kernel.org/r/20191011132931.1186197-3-gregkh@linuxfoundation.org
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
This commit is contained in:
Greg Kroah-Hartman
2019-10-11 15:29:26 +02:00
parent 313f5dbba4
commit ad26221fb9
3 changed files with 9 additions and 22 deletions
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4
Documentation/filesystems/debugfs.txt
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@@ -74,8 +74,8 @@ created with any of:
struct dentry *parent, u16 *value);
struct dentry *debugfs_create_u32(const char *name, umode_t mode,
struct dentry *parent, u32 *value);
struct dentry *debugfs_create_u64(const char *name, umode_t mode,
struct dentry *parent, u64 *value);
void debugfs_create_u64(const char *name, umode_t mode,
struct dentry *parent, u64 *value);
These files support both reading and writing the given value; if a specific
file should not be written to, simply set the mode bits accordingly. The