debugfs: Have debugfs_print_regs32() return void
The seq_printf() will soon just return void, and seq_has_overflowed() should be used instead to see if the seq can no longer accept input. As the return value of debugfs_print_regs32() has no users and the seq_file descriptor should be checked with seq_has_overflowed() instead of return values of functions, it is better to just have debugfs_print_regs32() also return void. Link: http://lkml.kernel.org/p/2634b19eb1c04a9d31148c1fe6f1f3819be95349.1412031505.git.joe@perches.com Acked-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org> Signed-off-by: Joe Perches <joe@perches.com> [ original change only updated seq_printf() return, added return of void to debugfs_print_regs32() as well ] Signed-off-by: Steven Rostedt <rostedt@goodmis.org>
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Steven Rostedt

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@@ -140,7 +140,7 @@ file.
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struct dentry *parent,
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struct debugfs_regset32 *regset);
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int debugfs_print_regs32(struct seq_file *s, struct debugfs_reg32 *regs,
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void debugfs_print_regs32(struct seq_file *s, struct debugfs_reg32 *regs,
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int nregs, void __iomem *base, char *prefix);
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The "base" argument may be 0, but you may want to build the reg32 array
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