debugfs: Have debugfs_print_regs32() return void

The seq_printf() will soon just return void, and seq_has_overflowed()
should be used instead to see if the seq can no longer accept input.

As the return value of debugfs_print_regs32() has no users and
the seq_file descriptor should be checked with seq_has_overflowed()
instead of return values of functions, it is better to just have
debugfs_print_regs32() also return void.

Link: http://lkml.kernel.org/p/2634b19eb1c04a9d31148c1fe6f1f3819be95349.1412031505.git.joe@perches.com

Acked-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
Signed-off-by: Joe Perches <joe@perches.com>
[ original change only updated seq_printf() return, added return of
  void to debugfs_print_regs32() as well ]
Signed-off-by: Steven Rostedt <rostedt@goodmis.org>
This commit is contained in:
Joe Perches
2014-09-29 16:08:26 -07:00
committed by Steven Rostedt
parent a3816ab0e8
commit 9761536e1d
3 changed files with 12 additions and 12 deletions

View File

@@ -140,7 +140,7 @@ file.
struct dentry *parent,
struct debugfs_regset32 *regset);
int debugfs_print_regs32(struct seq_file *s, struct debugfs_reg32 *regs,
void debugfs_print_regs32(struct seq_file *s, struct debugfs_reg32 *regs,
int nregs, void __iomem *base, char *prefix);
The "base" argument may be 0, but you may want to build the reg32 array