rcu: Don't return a value from rcu_assign_pointer()
Quoting Paul [1]: "Given that a quick (and perhaps error-prone) search of the uses of rcu_assign_pointer() in v5.1 didn't find a single use of the return value, let's please instead change the documentation and implementation to eliminate the return value." [1] https://lkml.kernel.org/r/20190523135013.GL28207@linux.ibm.com Signed-off-by: Andrea Parri <andrea.parri@amarulasolutions.com> Cc: "Paul E. McKenney" <paulmck@linux.ibm.com> Cc: Josh Triplett <josh@joshtriplett.org> Cc: Steven Rostedt <rostedt@goodmis.org> Cc: Mathieu Desnoyers <mathieu.desnoyers@efficios.com> Cc: Lai Jiangshan <jiangshanlai@gmail.com> Cc: Joel Fernandes <joel@joelfernandes.org> Cc: rcu@vger.kernel.org Cc: Peter Zijlstra <peterz@infradead.org> Cc: Will Deacon <will.deacon@arm.com> Cc: Mark Rutland <mark.rutland@arm.com> Cc: Matthew Wilcox <willy@infradead.org> Cc: Sasha Levin <sashal@kernel.org> Signed-off-by: Paul E. McKenney <paulmck@linux.ibm.com>
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Paul E. McKenney

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@@ -19,7 +19,7 @@ static inline bool rcu_is_watching(void)
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return false;
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}
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#define rcu_assign_pointer(p, v) ((p) = (v))
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#define RCU_INIT_POINTER(p, v) p=(v)
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#define rcu_assign_pointer(p, v) do { (p) = (v); } while (0)
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#define RCU_INIT_POINTER(p, v) do { (p) = (v); } while (0)
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#endif
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