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[NET] NETNS: Omit namespace comparision without CONFIG_NET_NS.

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Introduce an inline net_eq() to compare two namespaces.
Without CONFIG_NET_NS, since no namespace other than &init_net
exists, it is always 1.

We do not need to convert 1) inline vs inline and
2) inline vs &init_net comparisons.

Signed-off-by: YOSHIFUJI Hideaki <yoshfuji@linux-ipv6.org>
This commit is contained in:
YOSHIFUJI Hideaki
2008-03-26 03:57:35 +09:00
parent 57da52c1e6
commit 878628fbf2
14 changed files with 56 additions and 44 deletions
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4
net/unix/af_unix.c
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@@ -252,7 +252,7 @@ static struct sock *__unix_find_socket_byname(struct net *net,
sk_for_each(s, node, &unix_socket_table[hash ^ type]) {
struct unix_sock *u = unix_sk(s);
if (sock_net(s) != net)
if (!net_eq(sock_net(s), net))
continue;
if (u->addr->len == len &&
@@ -289,7 +289,7 @@ static struct sock *unix_find_socket_byinode(struct net *net, struct inode *i)
&unix_socket_table[i->i_ino & (UNIX_HASH_SIZE - 1)]) {
struct dentry *dentry = unix_sk(s)->dentry;
if (sock_net(s) != net)
if (!net_eq(sock_net(s), net))
continue;
if(dentry && dentry->d_inode == i)