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rxrpc: Provide a way for AFS to ask for the peer address of a call

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Provide a function so that kernel users, such as AFS, can ask for the peer
address of a call:

   void rxrpc_kernel_get_peer(struct rxrpc_call *call,
			      struct sockaddr_rxrpc *_srx);

In the future the kernel service won't get sk_buffs to look inside.
Further, this allows us to hide any canonicalisation inside AF_RXRPC for
when IPv6 support is added.

Also propagate this through to afs_find_server() and issue a warning if we
can't handle the address family yet.

Signed-off-by: David Howells <dhowells@redhat.com>
This commit is contained in:
David Howells
2016-08-30 09:49:29 +01:00
parent e0661dfc59
commit 8324f0bcfb
7 changed files with 48 additions and 14 deletions
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15
net/rxrpc/peer_object.c
View File

@@ -313,3 +313,18 @@ void __rxrpc_put_peer(struct rxrpc_peer *peer)
kfree_rcu(peer, rcu);
}
/**
* rxrpc_kernel_get_peer - Get the peer address of a call
* @sock: The socket on which the call is in progress.
* @call: The call to query
* @_srx: Where to place the result
*
* Get the address of the remote peer in a call.
*/
void rxrpc_kernel_get_peer(struct socket *sock, struct rxrpc_call *call,
struct sockaddr_rxrpc *_srx)
{
*_srx = call->peer->srx;
}
EXPORT_SYMBOL(rxrpc_kernel_get_peer);