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sched/core: Convert get_task_struct() to return the task

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Returning the pointer that was passed in allows us to write
slightly more idiomatic code.  Convert a few users.

Signed-off-by: Matthew Wilcox (Oracle) <willy@infradead.org>
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Link: https://lkml.kernel.org/r/20190704221323.24290-1-willy@infradead.org
Signed-off-by: Ingo Molnar <mingo@kernel.org>
This commit is contained in:
Matthew Wilcox (Oracle)
2019-07-04 15:13:23 -07:00
committed by Ingo Molnar
parent 3c29e651e1
commit 7b3c92b85a
5 changed files with 12 additions and 15 deletions
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6
include/linux/sched/task.h
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@@ -105,7 +105,11 @@ extern void sched_exec(void);
#define sched_exec() {}
#endif
#define get_task_struct(tsk) do { refcount_inc(&(tsk)->usage); } while(0)
static inline struct task_struct *get_task_struct(struct task_struct *t)
{
refcount_inc(&t->usage);
return t;
}
extern void __put_task_struct(struct task_struct *t);