sched: Rework pick_next_task() slow-path
Avoid the RETRY_TASK case in the pick_next_task() slow path. By doing the put_prev_task() early, we get the rt/deadline pull done, and by testing rq->nr_running we know if we need newidle_balance(). This then gives a stable state to pick a task from. Since the fast-path is fair only; it means the other classes will always have pick_next_task(.prev=NULL, .rf=NULL) and we can simplify. Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org> Cc: Aaron Lu <aaron.lwe@gmail.com> Cc: Valentin Schneider <valentin.schneider@arm.com> Cc: mingo@kernel.org Cc: Phil Auld <pauld@redhat.com> Cc: Julien Desfossez <jdesfossez@digitalocean.com> Cc: Nishanth Aravamudan <naravamudan@digitalocean.com> Link: https://lkml.kernel.org/r/aa34d24b36547139248f32a30138791ac6c02bd6.1559129225.git.vpillai@digitalocean.com
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@@ -1700,12 +1700,15 @@ struct sched_class {
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void (*check_preempt_curr)(struct rq *rq, struct task_struct *p, int flags);
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/*
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* It is the responsibility of the pick_next_task() method that will
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* return the next task to call put_prev_task() on the @prev task or
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* something equivalent.
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* Both @prev and @rf are optional and may be NULL, in which case the
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* caller must already have invoked put_prev_task(rq, prev, rf).
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*
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* May return RETRY_TASK when it finds a higher prio class has runnable
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* tasks.
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* Otherwise it is the responsibility of the pick_next_task() to call
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* put_prev_task() on the @prev task or something equivalent, IFF it
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* returns a next task.
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*
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* In that case (@rf != NULL) it may return RETRY_TASK when it finds a
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* higher prio class has runnable tasks.
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*/
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struct task_struct * (*pick_next_task)(struct rq *rq,
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struct task_struct *prev,
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