sched: Force the address order of each sched class descriptor
In order to make a micro optimization in pick_next_task(), the order of the sched class descriptor address must be in the same order as their priority to each other. That is: &idle_sched_class < &fair_sched_class < &rt_sched_class < &dl_sched_class < &stop_sched_class In order to guarantee this order of the sched class descriptors, add each one into their own data section and force the order in the linker script. Signed-off-by: Steven Rostedt (VMware) <rostedt@goodmis.org> Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org> Link: https://lore.kernel.org/r/157675913272.349305.8936736338884044103.stgit@localhost.localdomain
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committed by
Peter Zijlstra

parent
87e867b426
commit
590d697963
@@ -108,6 +108,18 @@
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#define SBSS_MAIN .sbss
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#endif
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/*
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* The order of the sched class addresses are important, as they are
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* used to determine the order of the priority of each sched class in
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* relation to each other.
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*/
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#define SCHED_DATA \
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*(__idle_sched_class) \
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*(__fair_sched_class) \
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*(__rt_sched_class) \
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*(__dl_sched_class) \
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*(__stop_sched_class)
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/*
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* Align to a 32 byte boundary equal to the
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* alignment gcc 4.5 uses for a struct
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@@ -388,6 +400,7 @@
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.rodata : AT(ADDR(.rodata) - LOAD_OFFSET) { \
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__start_rodata = .; \
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*(.rodata) *(.rodata.*) \
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SCHED_DATA \
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RO_AFTER_INIT_DATA /* Read only after init */ \
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. = ALIGN(8); \
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__start___tracepoints_ptrs = .; \
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