rcu: make rcutorture version numbers available through debugfs
It is not possible to accurately correlate rcutorture output with that of debugfs. This patch therefore adds a debugfs file that prints out the rcutorture version number, permitting easy correlation. Signed-off-by: Paul E. McKenney <paul.mckenney@linaro.org> Signed-off-by: Paul E. McKenney <paulmck@linux.vnet.ibm.com> Reviewed-by: Josh Triplett <josh@joshtriplett.org>
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zatwierdzone przez
Paul E. McKenney

rodzic
d71df90ead
commit
4a29865689
@@ -394,6 +394,29 @@ static const struct file_operations rcu_pending_fops = {
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.release = single_release,
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};
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static int show_rcutorture(struct seq_file *m, void *unused)
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{
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seq_printf(m, "rcutorture test sequence: %lu %s\n",
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rcutorture_testseq >> 1,
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(rcutorture_testseq & 0x1) ? "(test in progress)" : "");
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seq_printf(m, "rcutorture update version number: %lu\n",
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rcutorture_vernum);
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return 0;
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}
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static int rcutorture_open(struct inode *inode, struct file *file)
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{
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return single_open(file, show_rcutorture, NULL);
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}
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static const struct file_operations rcutorture_fops = {
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.owner = THIS_MODULE,
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.open = rcutorture_open,
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.read = seq_read,
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.llseek = seq_lseek,
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.release = single_release,
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};
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static struct dentry *rcudir;
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static int __init rcutree_trace_init(void)
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@@ -430,6 +453,11 @@ static int __init rcutree_trace_init(void)
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NULL, &rcu_pending_fops);
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if (!retval)
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goto free_out;
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retval = debugfs_create_file("rcutorture", 0444, rcudir,
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NULL, &rcutorture_fops);
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if (!retval)
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goto free_out;
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return 0;
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free_out:
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debugfs_remove_recursive(rcudir);
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