nohz: Use IPI implicit full barrier against rq->nr_running r/w

A full dynticks CPU is allowed to stop its tick when a single task runs.
Meanwhile when a new task gets enqueued, the CPU must be notified so that
it can restart its tick to maintain local fairness and other accounting
details.

This notification is performed by way of an IPI. Then when the target
receives the IPI, we expect it to see the new value of rq->nr_running.

Hence the following ordering scenario:

   CPU 0                   CPU 1

   write rq->running       get IPI
   smp_wmb()               smp_rmb()
   send IPI                read rq->nr_running

But Paul Mckenney says that nowadays IPIs imply a full barrier on
all architectures. So we can safely remove this pair and rely on the
implicit barriers that come along IPI send/receive. Lets
just comment on this new assumption.

Acked-by: Peter Zijlstra <peterz@infradead.org>
Cc: Andrew Morton <akpm@linux-foundation.org>
Cc: Ingo Molnar <mingo@kernel.org>
Cc: Kevin Hilman <khilman@linaro.org>
Cc: Paul E. McKenney <paulmck@linux.vnet.ibm.com>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Cc: Viresh Kumar <viresh.kumar@linaro.org>
Signed-off-by: Frederic Weisbecker <fweisbec@gmail.com>
此提交包含在:
Frederic Weisbecker
2014-03-18 22:54:04 +01:00
父節點 fd2ac4f4a6
當前提交 3882ec6439
共有 2 個檔案被更改,包括 13 行新增6 行删除

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@@ -1221,8 +1221,14 @@ static inline void add_nr_running(struct rq *rq, unsigned count)
#ifdef CONFIG_NO_HZ_FULL
if (prev_nr < 2 && rq->nr_running >= 2) {
if (tick_nohz_full_cpu(rq->cpu)) {
/* Order rq->nr_running write against the IPI */
smp_wmb();
/*
* Tick is needed if more than one task runs on a CPU.
* Send the target an IPI to kick it out of nohz mode.
*
* We assume that IPI implies full memory barrier and the
* new value of rq->nr_running is visible on reception
* from the target.
*/
tick_nohz_full_kick_cpu(rq->cpu);
}
}