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gpu: ipu-v3: ipu-dmfc: Make function ipu_dmfc_init_channel() return void

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Since the function ipu_dmfc_init_channel() always returns zero, we may
change the return type to void to simplify the code.

Signed-off-by: Liu Ying <gnuiyl@gmail.com>
Signed-off-by: Philipp Zabel <p.zabel@pengutronix.de>
This commit is contained in:
Liu Ying
2016-03-14 16:10:09 +08:00
committed by Philipp Zabel
parent 32c26a56af
commit 2bbe32f739
3 changed files with 3 additions and 9 deletions
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4
drivers/gpu/ipu-v3/ipu-dmfc.c
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@@ -350,7 +350,7 @@ out:
}
EXPORT_SYMBOL_GPL(ipu_dmfc_alloc_bandwidth);
int ipu_dmfc_init_channel(struct dmfc_channel *dmfc, int width)
void ipu_dmfc_init_channel(struct dmfc_channel *dmfc, int width)
{
struct ipu_dmfc_priv *priv = dmfc->priv;
u32 dmfc_gen1;
@@ -367,8 +367,6 @@ int ipu_dmfc_init_channel(struct dmfc_channel *dmfc, int width)
writel(dmfc_gen1, priv->base + DMFC_GENERAL1);
mutex_unlock(&priv->mutex);
return 0;
}
EXPORT_SYMBOL_GPL(ipu_dmfc_init_channel);