drm/ttm: remove dummy bo_move implementations

It's pointless to only call the default implementation.

Reviewed-by: Alex Deucher <alexander.deucher@amd.com>
Signed-off-by: Christian König <christian.koenig@amd.com>
Signed-off-by: Alex Deucher <alexander.deucher@amd.com>
此提交包含在:
Christian König
2016-06-06 10:17:52 +02:00
提交者 Alex Deucher
父節點 4279cb1423
當前提交 1888577807
共有 4 個檔案被更改,包括 4 行新增46 行删除

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@@ -186,17 +186,6 @@ static void cirrus_ttm_io_mem_free(struct ttm_bo_device *bdev, struct ttm_mem_re
{
}
static int cirrus_bo_move(struct ttm_buffer_object *bo,
bool evict, bool interruptible,
bool no_wait_gpu,
struct ttm_mem_reg *new_mem)
{
int r;
r = ttm_bo_move_memcpy(bo, evict, no_wait_gpu, new_mem);
return r;
}
static void cirrus_ttm_backend_destroy(struct ttm_tt *tt)
{
ttm_tt_fini(tt);
@@ -241,7 +230,7 @@ struct ttm_bo_driver cirrus_bo_driver = {
.ttm_tt_unpopulate = cirrus_ttm_tt_unpopulate,
.init_mem_type = cirrus_bo_init_mem_type,
.evict_flags = cirrus_bo_evict_flags,
.move = cirrus_bo_move,
.move = NULL,
.verify_access = cirrus_bo_verify_access,
.io_mem_reserve = &cirrus_ttm_io_mem_reserve,
.io_mem_free = &cirrus_ttm_io_mem_free,