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hexdump: make it return number of bytes placed in buffer

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This patch makes hexdump return the number of bytes placed in the buffer
excluding trailing NUL.  In the case of overflow it returns the desired
amount of bytes to produce the entire dump.  Thus, it mimics snprintf().

This will be useful for users that would like to repeat with a bigger
buffer.

[akpm@linux-foundation.org: fix printk warning]
Signed-off-by: Andy Shevchenko <andriy.shevchenko@linux.intel.com>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
Andy Shevchenko
2015-02-12 15:02:29 -08:00
committed by Linus Torvalds
parent 5d909c8d54
commit 114fc1afb2
3 changed files with 103 additions and 21 deletions
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45
lib/test-hexdump.c
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@@ -114,6 +114,45 @@ static void __init test_hexdump_set(int rowsize, bool ascii)
test_hexdump(len, rowsize, 1, ascii);
}
static void __init test_hexdump_overflow(bool ascii)
{
char buf[56];
const char *t = test_data_1_le[0];
size_t l = get_random_int() % sizeof(buf);
bool a;
int e, r;
memset(buf, ' ', sizeof(buf));
r = hex_dump_to_buffer(data_b, 1, 16, 1, buf, l, ascii);
if (ascii)
e = 50;
else
e = 2;
buf[e + 2] = '\0';
if (!l) {
a = r == e && buf[0] == ' ';
} else if (l < 3) {
a = r == e && buf[0] == '\0';
} else if (l < 4) {
a = r == e && !strcmp(buf, t);
} else if (ascii) {
if (l < 51)
a = r == e && buf[l - 1] == '\0' && buf[l - 2] == ' ';
else
a = r == e && buf[50] == '\0' && buf[49] == '.';
} else {
a = r == e && buf[e] == '\0';
}
if (!a) {
pr_err("Len: %zu rc: %u strlen: %zu\n", l, r, strlen(buf));
pr_err("Result: '%s'\n", buf);
}
}
static int __init test_hexdump_init(void)
{
unsigned int i;
@@ -129,6 +168,12 @@ static int __init test_hexdump_init(void)
for (i = 0; i < 16; i++)
test_hexdump_set(rowsize, true);
for (i = 0; i < 16; i++)
test_hexdump_overflow(false);
for (i = 0; i < 16; i++)
test_hexdump_overflow(true);
return -EINVAL;
}
module_init(test_hexdump_init);