debugfs: remove return value of debugfs_create_devm_seqfile()
No one checks the return value of debugfs_create_devm_seqfile(), as it's not needed, so make the return value void, so that no one tries to do so in the future. Link: https://lore.kernel.org/r/20201023131037.2500765-1-gregkh@linuxfoundation.org Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
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@@ -1127,24 +1127,23 @@ static const struct file_operations debugfs_devm_entry_ops = {
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* file will be created in the root of the debugfs filesystem.
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* @read_fn: function pointer called to print the seq_file content.
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*/
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struct dentry *debugfs_create_devm_seqfile(struct device *dev, const char *name,
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struct dentry *parent,
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int (*read_fn)(struct seq_file *s,
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void *data))
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void debugfs_create_devm_seqfile(struct device *dev, const char *name,
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struct dentry *parent,
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int (*read_fn)(struct seq_file *s, void *data))
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{
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struct debugfs_devm_entry *entry;
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if (IS_ERR(parent))
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return ERR_PTR(-ENOENT);
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return;
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entry = devm_kzalloc(dev, sizeof(*entry), GFP_KERNEL);
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if (!entry)
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return ERR_PTR(-ENOMEM);
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return;
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entry->read = read_fn;
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entry->dev = dev;
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return debugfs_create_file(name, S_IRUGO, parent, entry,
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&debugfs_devm_entry_ops);
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debugfs_create_file(name, S_IRUGO, parent, entry,
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&debugfs_devm_entry_ops);
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}
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EXPORT_SYMBOL_GPL(debugfs_create_devm_seqfile);
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