ipvs: Pass ipvs into conn_out_get
Move the hack of relying on "net_ipvs(skb_net(skb))" to derive the ipvs up a layer. Signed-off-by: "Eric W. Biederman" <ebiederm@xmission.com> Acked-by: Julian Anastasov <ja@ssi.bg> Signed-off-by: Simon Horman <horms@verge.net.au>
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Simon Horman

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0cf705c8c2
@@ -499,7 +499,8 @@ struct ip_vs_protocol {
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const struct ip_vs_iphdr *iph);
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struct ip_vs_conn *
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(*conn_out_get)(int af,
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(*conn_out_get)(struct netns_ipvs *ipvs,
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int af,
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const struct sk_buff *skb,
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const struct ip_vs_iphdr *iph);
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@@ -1229,7 +1230,8 @@ struct ip_vs_conn * ip_vs_conn_in_get_proto(struct netns_ipvs *ipvs, int af,
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struct ip_vs_conn *ip_vs_conn_out_get(const struct ip_vs_conn_param *p);
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struct ip_vs_conn * ip_vs_conn_out_get_proto(int af, const struct sk_buff *skb,
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struct ip_vs_conn * ip_vs_conn_out_get_proto(struct netns_ipvs *ipvs, int af,
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const struct sk_buff *skb,
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const struct ip_vs_iphdr *iph);
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/* Get reference to gain full access to conn.
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